Note that the base of the log should correspond to the base of the exponential part of the equation, so that the log cancels out the exponential function, leaving out only the exponent. If we can make ...
\({\log _a}a = 1\) (since \({a^1} = a\)) so \({\log _7}7 = 1\) \({\log _a}1 = 0\) (since \({a^0} = 1\)) so \({\log _{20}}1 = 0\) \({\log _a}p + {\log _a}q = {\log _a ...
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