Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.

Candidates preparing for JEE Advanced 2026 can download the official syllabus PDF from jeeadv.ac.in, released by IIT Roorkee.

Welcome to your guide to Pips, the latest game in the New York Times catalogue. Released in August 2025, the Pips puts a unique spin on dominoes, creating a fun single-player experience that could ...

To be eligible for JEE Advanced 2026, candidates must rank among the top 2.5 lakh students in JEE Main 2026, satisfy the age criteria. Additionally, candidates must have appeared for their Class 12 ...